 تم الانتقال إلى زاوية ميل 10° حيث

 تم الانتقال إلى زاوية ميل 10° حيث كانت أقل قيمة هي 6.72 والتي كانت في شهر ديسمبر أيضا، وعند المقارنة بينها وبين القيمة لزاوية الميل صفر° وجد أنها أكبر لذا تم الانتقال إلى زاوية الميل التالية (زاوية ميل 15)، (كمية الإشعاع الشمسي لميل 10 هو 6.72 أكبر من القيمة عند زاوية ميل صفر التي هي 5.89).

Results (English) 1:

 We moved to an inclination angle of 10°, as the lowest value was 6.72, which was also in December. When comparing it with the value for the inclination angle of 0°, it was found that it was greater, so we moved to the next inclination angle (inclination angle of 15), (amount of solar radiation). For a slope of 10, it is 6.72 greater than the value at zero slope, which is 5.89).

Results (English) 2:

Move to a 10 ° inclination angle, with a minimum value of 6.72, which was also in December. When compared with the 0 ° inclination angle, it was found to be larger, so move to the next inclination angle (15 mile angle). The solar radiation at 10 miles is 6.72 more than the value of 5.89 at 0 miles

Results (English) 3:

Move to an angle of 10, where the minimum value is 6.72, and in December, when it is compared with the angle of 0, it is found to be larger, so move to the next angle (an angle of 15), (the solar radiation of 10 is greater than the value of 6.72, and it is 5.89 at a zero-mile angle).